3x^2+8x-6.5=0

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Solution for 3x^2+8x-6.5=0 equation:



3x^2+8x-6.5=0
a = 3; b = 8; c = -6.5;
Δ = b2-4ac
Δ = 82-4·3·(-6.5)
Δ = 142
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-\sqrt{142}}{2*3}=\frac{-8-\sqrt{142}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+\sqrt{142}}{2*3}=\frac{-8+\sqrt{142}}{6} $

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